If 1+4=5, 2+5=12, 3+6=21
If 1+4=5, 2+5=12, 3+6=21


Here are five ways people have approached this problem: Solution 1 (Formula: A + A × B × B = C) 1 + 4 = 5 2 + 5 = 2 + 2(5) = 12 3 + 6 = 3 + 3(6) = 21 5 + 8 = 5 + 5(8) = 45 ✅ Answer: 45 Solution 2 (Using the previous result) 1 + 4 = 5 2 + 5 = 2 + 5 + (previous answer: 5) = 12 3 + 6 = 3 + 6 + (previous answer: 12) = 21 5 + 8 = 5 + 8 + (previous answer: 21) = 34 ✅ Answer: 34 Solution 3 (Accumulating Sum) 1 + 4 = 5 2 + 5 = (5 + 2) + (5) = 12 3 + 6 = (7 + 2) + (12) = 21 5 + 8 = (9 + 2) + (21) = 32 ✅ Answer: 32 Solution 4 (Number System) 1 + 4 = 5 (in the regular system) 2 + 5 = 7 (in the penta system) = 12 3 + 6 = 9 (in the quaternary system) = 21 5 + 8 = 13 (in the ternary system) = 111 ✅ Answer: 111 Solution 5 (Using different number systems) 1 + 4 = 5 2 + 5 = 7 (in the penta system) = 12 3 + 6 = 9 (in the quaternary system) = 21 4 + 7 = 11 (in the ternary system) = 102 5 + 8 = 13 (in the binary system) = 1101 ✅ Answer: 1101 Conclusion This problem does not have a single correct answer because it is based on different logic circuits.
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