If 1+4=5, 2+5=12, 3+6=21

, what is 5+8? If you are like me, you are probably thankful that the last time you solved a difficult maths problem was at school. I know that there are people who love maths, just as there are those who hate it (I am one of them). I prefer creativity to logical thinking, but we are all different. Nevertheless, even though maths was not my favourite subject at school, I suddenly found pleasure in solving puzzles and riddles on the internet. And I know I am not the only one. Many people pride themselves on their ability to spot patterns and solve complex maths problems.The puzzle that stumped the internet We decided to test our readers’ abilities and offer you a problem that has left thousands of people puzzling.Ready to turn on the logic? Then here is the problem: If 1+4=5, 2+5=12, 3+6=21, then 5+8=? On the Internet this example has caused heated debates, because it can have several correct answers. It all depends on the method of solution.

Here are five ways people have approached this problem: Solution 1 (Formula: A + A × B × B = C) 1 + 4 = 5 2 + 5 = 2 + 2(5) = 12 3 + 6 = 3 + 3(6) = 21 5 + 8 = 5 + 5(8) = 45 ✅ Answer: 45 Solution 2 (Using the previous result) 1 + 4 = 5 2 + 5 = 2 + 5 + (previous answer: 5) = 12 3 + 6 = 3 + 6 + (previous answer: 12) = 21 5 + 8 = 5 + 8 + (previous answer: 21) = 34 ✅ Answer: 34 Solution 3 (Accumulating Sum) 1 + 4 = 5 2 + 5 = (5 + 2) + (5) = 12 3 + 6 = (7 + 2) + (12) = 21 5 + 8 = (9 + 2) + (21) = 32 ✅ Answer: 32 Solution 4 (Number System) 1 + 4 = 5 (in the regular system) 2 + 5 = 7 (in the penta system) = 12 3 + 6 = 9 (in the quaternary system) = 21 5 + 8 = 13 (in the ternary system) = 111 ✅ Answer: 111 Solution 5 (Using different number systems) 1 + 4 = 5 2 + 5 = 7 (in the penta system) = 12 3 + 6 = 9 (in the quaternary system) = 21 4 + 7 = 11 (in the ternary system) = 102 5 + 8 = 13 (in the binary system) = 1101 ✅ Answer: 1101 Conclusion This problem does not have a single correct answer because it is based on different logic circuits.

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